help! please simplify this shell program!

Pacific Yan

#!/usr/bin/ksh

case $# in
      0) year='date | awk '{print $6}'';;
      [1-9]*([0-9])) year=$1
          if ((year<1)) || ((year>9999))
          then
          echo "year must be 1 to 9999"
          exit 1
          fi;;
esac


# initialize variables
Mon=0 Tue=0 Wed=0 Thu=0 Fri=0 Sat=0 Sun=0

for count in 1 2 3 4 5 6 7 8 9 10 11 12
do
    if [ "'cal $count $year | sed -n '3p' | awk '/^ 1/{print}''" !=""]
    then Sun='expr $sun + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^    1/{print}''" !=""]
    then Mon='expr $Mon + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^       1/{print}''" !=""]
    then Tue='expr $Tue + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^          1/{print}''" !=""]
    then Wed='expr $Wed + 1'
    fi
   
    if [ "'cal $count $year | sed -n '3p' | awk '/^             1/{print}''" !=""]
    then Thu='expr $Thu + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^                1/{print}''" !=""]
    then Fri='expr $Fri + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^                   1/{print}''" !=""]
    then Sat='expr $Sat + 1'
    fi
done

echo "Sunday $Sun\nMonday $Mon\nTuesday $Tue\nWednesday $Wed\nThursday $Thu\nFriday $Fri\nsaturday $Sat |Sort +1 -n |sed -n '7p' | awk '{print $1}'

nkliyong

完成的是什么功能啊?

最起码几个if then.....fi可以合并到一起.

Pacific Yan

a program to report the weekday that occurs to be the first day of the month most often within a given year

Pacific Yan

Actually, these if and then are different,

awk '/^ (one space between)1/{print}''" !=""]  for sunday

awk '/^ (3 space between)1/{print}''" !=""]  for Monday

and so on,

I just want to extract a line which match to day 1 and also tell me what weekday it is.





#!/usr/bin/ksh

case $# in
      0) year='date | awk '{print $6}'';;
      [1-9]*([0-9])) year=$1
          if ((year<1)) || ((year>9999))
          then
          echo "year must be 1 to 9999"
          exit 1
          fi;;
esac


# initialize variables
Mon=0 Tue=0 Wed=0 Thu=0 Fri=0 Sat=0 Sun=0

for count in 1 2 3 4 5 6 7 8 9 10 11 12
do
    if [ "'cal $count $year | sed -n '3p' | awk '/^ 1/{print}''" !=""]
    then Sun='expr $sun + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^    1/{print}''" !=""]
    then Mon='expr $Mon + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^       1/{print}''" !=""]
    then Tue='expr $Tue + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^          1/{print}''" !=""]
    then Wed='expr $Wed + 1'
    fi
   
    if [ "'cal $count $year | sed -n '3p' | awk '/^             1/{print}''" !=""]
    then Thu='expr $Thu + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^                1/{print}''" !=""]
    then Fri='expr $Fri + 1'
    fi

    if [ "'cal $count $year | sed -n '3p' | awk '/^                   1/{print}''" !=""]
    then Sat='expr $Sat + 1'
    fi
done

echo "Sunday $Sun\nMonday $Mon\nTuesday $Tue\nWednesday $Wed\nThursday $Thu\nFriday $Fri\nsaturday $Sat |Sort +1 -n |sed -n '7p' | awk '{print $1}'

nkliyong

是不是你的空格又被系统吃啦!你可以把你的代码写在

1. 
   
2. 代码
   

复制代码

这样就能看到完整的格式啦.

你能用中文说明程序的目的吗?

Pacific Yan

I don't know how to input Chinese in my computer.

I guess your guys are expert and it is a piece of cake to you.

powerplane

原帖由 "acific Yan" 发表：
I don't know how to input Chinese in my computer.

I guess your guys are expert and it is a piece of cake to you.

   
Then use another computer, show your respects to Gurus....

Pacific Yan

Sorry, guys, I am not trying to offend anybody.  Tell you truth, I don't know how to input Chinese at all even you can offer me a good Chinese software.  My poor China Countryside education system

夜未眠

是不是报告指定年份的每个月的第一天是星期几的程式啊?

Pacific Yan

yes, you are really good! By the way, I am a bioinformatics and a biologist, and I am not a good programmer.  So, I am trying to learn something.  Also, do your guys have any any idea want to do something related to that area in China?