help! please simplify this shell program!

夜未眠

免费吗？免费就要啦.

Pacific Yan

of course, it is free.  I have a lot of ebooks about oracle, linux shell and also PERL, but for the hard copies, I guess the shipping fee is too much.

Pacific Yan

Here is my testing, it looks like for 2 arguments are OK, but for one argument, I got no output, and also one small output error I guess I need to figure it out.  All the output errors are marked as below:

$ newtest.sh 2003 2009
newtest.sh[5]:  :  not found   <<<<<<<<<<< This isn't what I want
Friday

xyan<176>newtest.sh 2003    <<<<<<<<<<<< no output


xyan<178>newtest.sh 2001 2003
newtest.sh[5]:  :  not found        <<<<<<<<the same errors
Wednesday

xyan<182>newtest.sh 2003 2005
newtest.sh[5]:  :  not found       <<<<<<<<the same errors
Sunday Friday

The results are all correct.

Thanks, 夜未眠, this project cost me a lot of time.  I really appreciate your efforts and kindness.

夜未眠

如果要计算某一年.如果你不怕麻烦的话给newtest.sh传递两个相同的参数就可以了. 也不知道你给这个sh传一个参数时是想得到当年统计次数最少的还是全部都显示(象前面的test.sh一样)

比如要得到2003年的，这样计算出来的是2003年出现次数最少的

1. 
   
2. $ ./newtest.sh 2003 2003
   
3. Sunday Thursday Friday
   
4. $
   

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如果非要用一个参数的话那么把程序开头的那段if语句改一下.

1. 
   
2. if [ $# -ne 2 ];then exit 1;fi
   
3. if [ $1 -ge 1 ] && [ $1 -le 9999 ] && \
   
4.         [ $2 -ge 1 ] && [ $2 -le 9999 ];then
   
5. 
   
6. if [ $1 -gt $2 ];then from=$2;to=$1;else from=$1;to=$2;fi
   

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改为

1. 
   
2. if [ $# -gt 2 ];then exit 1;fi
   
3. if [ $# -eq 1 ];then v1=$1;v2=$1;else v1=$1;v2=$2;fi
   
4. if [ $v1 -ge 1 ] && [ $v1 -le 9999 ] && \
   
5.         [ $v2 -ge 1 ] && [ $v2 -le 9999 ];then
   
6. if [ $v1 -gt $v2 ];then from=$v2;to=$v1;else from=$v1;to=$v2;fi
   

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实际上这种方法很笨的。 就是把一个的参数人为的设为两个相同的参数，如果要更高的效率的话应该改程式结构。而不应该象这样改。还有就是参数检查，如果只是自己用的话没必要加那么大一段的参数检查。如果果我自己用的话我就会删除这些检查输入参数在1-9999的语句.至于那些not found错误我就不清楚了。在freebsd下正常，不了解你的系统  

Pacific Yan

Thanks very much! It works.  

related to some useless code, it is my stupid assignment's requirement.

Pacific Yan

Hi, can you send the file and your phone number to xyan0@yahoo.com again? my company block your email because it is a shell script.  Thanks

ewancarrey

to LZ
you can read Chinese , but why can't you type it?!
you can do things on the cyber,why can't you download a software to input Chinese?!!

r2007

原帖由 ewancarrey 于 2007-6-22 18:42 发表
to LZ
you can read Chinese , but why can't you type it?!
you can do things on the cyber,why can't you download a software to input Chinese?!!

刨坟啊？
N年前我也同样质问过我的一个朋友，甚至说如果找不到可以帮他找，详细一问，是苹果机。我晕！经过一顿狂搜，终无果。或许没找对路，总之很难找，八成当时就没有。

lostwolf

date -d "20010101" +"%a"

awk就是awp加ak

try

1. 
   
2. YEAR=2001
   
3. seq 12 |sed "s,^,${YEAR}-," |awk '
   
4. BEGIN {
   
5.         initWeekTable();
   
6. }
   
7. 
   
8. function initWeekTable(){
   
9. 
   
10.         _week[0] = "Sunday";
    
11.         _week[1] = "Monday";
    
12.         _week[2] = "Tuesday";
    
13.         _week[3] = "Wednesday";
    
14.         _week[4] = "Thursday";
    
15.         _week[5] = "Friday";
    
16.         _week[6] = "Saturday";       
    
17. }
    
18. 
    
19. function isLeapYear(pYear){
    
20. 
    
21.         return pYear % 400 || pYear % 4 && !(pYear % 100);
    
22. }
    
23. 
    
24. function dispWeek(pWeek){
    
25. 
    
26.         return _week[pWeek];
    
27. }
    
28. 
    
29. # date format: 2007[-06[-20]]
    
30. function dateToWeek(pDate, tmpArr, count, year, month, day, days){
    
31. 
    
32.         count = split(pDate, tmpArr, "-");
    
33. 
    
34.         year = tmpArr[1]+0;
    
35.         month = count > 1 ? tmpArr[2]+0 : 1;
    
36.         day = count > 2 ? tmpArr[3]+0 : 1;
    
37. 
    
38.         days = year-1 + int(year/4) - int(year/100) + int(year/400);
    
39.         days += 2 * (month-1) + int(month/2) + int((month-1)/8);
    
40.         if (month > 3) {
    
41. 
    
42.                 if (!isLeapYear(year)) days--;
    
43.                 else days -= 2;
    
44.         }
    
45. 
    
46.         return (days + day) % 7;
    
47. }
    
48. 
    
49. {
    
50.         sum[dispWeek(dateToWeek($0))]++;
    
51. }
    
52. 
    
53. END {
    
54. 
    
55.         for (i in sum) print i " " sum[i];
    
56. }' |sort -n -k2 |cut -d' ' -f1

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