help! please simplify this shell program!

Pacific Yan

if I add -n, then will give me this:

$ test1.sh 2003
-n Sunday
-n Thursday
-n Friday

夜未眠

原帖由 "acific Yan" 发表：
You are right, this line failed, but it works in Compaq Tru64 and also IBM, but doesn't work in SunOS 5.8, why?

see the following example in Tru64 korn shell:

$ cat sorttest
Friday 1
Sunday 1
..........

一个文件使用一个 BEGIN,END对.

而上面的echo |awk 是一行就要使用一个BEGIN,END对.

夜未眠

man echo看看

Pacific Yan

Great !!!!  It works!  You are my hero!  


$ cat >test1.sh
#!/usr/bin/ksh
if [ $# -ne 1 ];then exit 1;fi
if [ $1 -ge 1 ] && [ $1 -le 9999 ];then

da=0
for st in Sunday Monday Tuesday Wednesday Thursday Friday Saturday;do
        eval str_$da=$st
        da=$(($da + 1))
done

mon=1
while [ $mon -le 12 ];do
        da=`cal $mon $1 |awk 'NR==3{loc=index($0,"1";print (loc-2)/3;exit}'`
        eval "count_$da=\$((\$count_$da+1))"
        mon=$(($mon + 1 ))
done

da=0
while [ $da -le 6 ];do
        eval dcn=\$count_$da
        if [ $dcn -eq 1 ];then
                eval "print \"\$str_$da \""|awk 'BEGIN {OFS=" "; ORS=" "} {print $1}
'
fi
        da=$(($da + 1))
done
echo
fi

$ test1.sh 2003
Sunday Thursday Friday

夜未眠

nothing
有空到ChongQing/HangZhou来玩,


--------------------------------主要是想你开饭.或带点儿美利坚的小玩意儿玩玩.

Pacific Yan

No problem, I work for a company and also as a part-time student at the same time.


keep in touch!

夜未眠

我的妹儿: bsdi@sina.com
你的呢？

Pacific Yan

my email: xyan0@yahoo.com

I will give you my phone number in my email.

夜未眠

ok.
太晚了,我要去睡觉了。
祝自己晚安。不知你那儿是几点？呵呵.

Pacific Yan

It is great that the above program can take one argument, now how can I modify this program and let it can take two arguments?

for example:

$ test.sh 2003 2007  or $ test.sh 2007 2003  (the order should not be matter)

It will consider the years 2003 2004 2005 2006 2007, then add all of them together and export the results like before where the weekdays are separated by a single space and in ascending order.

Do I have to do like this? Why it doesn’t work?







#!/usr/bin/ksh

#case where 2 years were supplied         
         
if ((aNumber<1)) || ((aNumber>9999)) || ((anotherNumber<1)) || ((anotherNumber>9999))
           then
             echo "year must be 1 to 9999"
             exit 1
fi
           
if ((aNumber>anotherNumber)); then
             temp=$aNumber aNumber=$anotherNumber anotherNumber=$temp
           
fi
           

da=0
for st in Sunday Monday Tuesday Wednesday Thursday Friday Saturday;do
        eval str_$da=$st
        da=$(($da + 1))
done

mon=1
while [ $mon -le 12 ];do
        da=`cal $mon $1 |awk 'NR==3{loc=index($0,"1";print (loc-2)/3;exit}'`
        eval "count_$da=\$((\$count_$da+1))"
        mon=$(($mon + 1 ))
done

da=0
while [ $da -le 6 ];do
        eval dcn=\$count_$da
        if [ $dcn -eq 1 ];then
                eval "print \"\$str_$da \""|awk 'BEGIN {OFS=" "; ORS=" "} {print $1} ' fi
        da=$(($da + 1))
done
echo
fi


cnt=0
           
Mon=0 Tue=0 Wed=0 Thu=0 Fri=0 Sat=0 Sun=0

str=`eval "print \"\$str_$da \""|awk 'BEGIN {OFS=" "; ORS=" "} {print $1}`’

case $str in
  "Sunday" ((Sun=$Sun+1));;
  "Monday" ((Mon=$Mon+1));;
  "Tuesday" ((Tue=$Tue+1));;
  "Wednesday" ((Wed=$Wed+1));;
  "Thursday" ((Thu=$Thu+1));;   
  "Friday" ((Fri=$Fri+1));;        
  "Saturday" ((Sat=$Sat+1));;  
esac
           
           
           
             ((cnt=$cnt+1))
           done
           
esac        
echo $finalstring  

#case where 2 years were supplied         [2-9]*([0-9])