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LZ的需求,我的代码改四个字节就能做到,可是何必呢= =贪心复杂度会更好的:- import re
- def pack(li, limit):
- limit = int(limit * 100)
- li = map(lambda x: int(x * 100), li)
- dp = [0] * (limit + 1)
- use = [[False] * len(li) for x in xrange(limit + 1)]
- for i in xrange(len(li)):
- for w in xrange(limit, li[i] - 1, -1):
- if dp[w] < dp[w - li[i]] + 1:
- dp[w] = dp[w - li[i]] + 1
- use[w] = use[w - li[i]][:]
- use[w][i] = True
- li = filter(None, map(lambda a, b: a and b, use[limit],
- map(lambda x: float(x) / 100, li)))
- return sum(li), li
- def solve(s):
- for line in filter(None, s.split("\n")):
- table = {}
- li = []
- for item in line.split():
- k, v = re.match("(.*):(.*)", item).group(1, 2)
- table[float(v)] = item
- li.append(v)
- ans = pack(map(float, li), 0.49)
- print ans[0], " ".join(table[v] for v in ans[1])
- solve("""
- a:0.13 b:0.23 c:0.05 d:0.45 e:0.07
- p:0.13 q:0.20 r:0.13 s:0.33 t:0.23
- h:0.08 g:0.11 r:0.05 y:0.45 s:0.24
- g:0.01 q:0.02 r:0.03 s:0.04 t:0.05
- g:0.21 q:0.22 r:0.03 s:0.04 t:0.05
- """)
复制代码python "noname\2010-09-29-2.py"
0.48 a:0.13 b:0.23 c:0.05 e:0.07
0.46 r:0.13 q:0.20 r:0.13
0.48 h:0.08 g:0.11 r:0.05 s:0.24
0.15 g:0.01 q:0.02 r:0.03 s:0.04 t:0.05
0.33 g:0.21 r:0.03 s:0.04 t:0.05
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