- 论坛徽章:
- 5
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本帖最后由 starwing83 于 2010-09-30 10:27 编辑
- import re
- def pack(li, limit, key = lambda x: x):
- dp = [0] * (limit + 1)
- use = [[False] * len(li) for x in xrange(limit + 1)]
- for i in xrange(len(li)):
- for w in xrange(limit, key(li[i]) - 1, -1):
- if dp[w] < dp[w - key(li[i])] + 1:
- dp[w] = dp[w - key(li[i])] + 1
- use[w] = use[w - key(li[i])][:]
- use[w][i] = True
- li = filter(None, map(lambda a, b: a and b, use[limit], li))
- return reduce(lambda a, b: a + key(b), li, 0), li
- def solve(s):
- for line in filter(None, s.split("\n")):
- li = [re.match("(.*):(.*)", item).group(1, 2)
- for item in line.split()]
- li = map(lambda x: (x[0], int(float(x[1]) * 100)), li)
- ans = pack(li, 49, key = lambda x: x[1])
- print float(ans[0]) / 100, " ".join(
- "%s:%.2f"%(v[0], float(v[1]) / 100) for v in ans[1])
- solve("""
- a:0.13 b:0.23 c:0.05 d:0.45 e:0.07
- p:0.13 q:0.20 r:0.13 s:0.33 t:0.23
- h:0.08 g:0.11 r:0.05 y:0.45 s:0.24
- g:0.01 q:0.02 r:0.03 s:0.04 t:0.05
- g:0.21 q:0.22 r:0.03 s:0.04 t:0.05
- """)
复制代码 这个是完全满足LZ要求的代码,虽然复杂度搓了点= = |
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