请教一个循环读取的问题

zhou0521

代码：
dbqserver=`ps aux|grep dbqserver|grep -v grep|wc -l`
adqserver=`ps aux|grep adqserver|grep -v grep|wc -l`
logserver=`ps aux|grep logserver|grep -v grep|wc -l`
httpapi=`ps aux|grep httpapi|grep -v grep|wc -l`
taskmgr=`ps aux|grep taskmgr|grep -v grep|wc -l`
name=(dbqserver adqserver logserver httpapi taskmgr)
for i in ${name[*]}
do
echo $i
if [ $i -eq 0 ];then
        echo "$i is down."
else
        echo "$i is runing."
fi
done
###################################
能跑起来，运行的时候是这样：
dbqserver
check.sh: line 44: [: dbqserver: integer expression expected
dbqserver is runing.
adqserver
check.sh: line 44: [: adqserver: integer expression expected
adqserver is runing.
logserver
check.sh: line 44: [: logserver: integer expression expected
logserver is runing.
httpapi
check.sh: line 44: [: httpapi: integer expression expected
httpapi is runing.
taskmgr
check.sh: line 44: [: taskmgr: integer expression expected
taskmgr is runing.
#############################
请问：check.sh: line 44: [: taskmgr: integer expression expected
是啥问题，怎么改过来

zhou0521

怎么让循环里执行变量里保存的命令呢？

waker

do
eval i=\$$i

hujysh

回复 2# zhou0521


   
[ $i -eq 0 ] 期望 i 是整数，实际是串，所以报错。

执行变量中保存的命令可以用 eval

zhou0521

谢谢大家，我是新手，见笑了