如何计算下面这样的时间差

lkf1100

我的数据类似于这样

1. FileName =20141002081204.black; BeginDate = 2014-10-02 08:13:37
   
2. FileName =20141002081204.black; EndDate = 2014-10-02 08:14:05
   
3. FileName =20141003081912.black; BeginDate = 2014-10-03 08:20:21
   
4. FileName =20141003081912.black; EndDate = 2014-10-03 08:21:02
   
5. FileName =20141004082626.black; BeginDate = 2014-10-04 08:27:22
   
6. FileName =20141004082626.black; EndDate = 2014-10-04 08:27:28
   
7. FileName =20141005081654.black; BeginDate = 2014-10-05 08:18:32
   
8. FileName =20141005081654.black; EndDate = 2014-10-05 08:19:24
   
9. FileName =20141006083608.black; BeginDate = 2014-10-06 08:37:43
   
10. FileName =20141006083608.black; EndDate = 2014-10-06 08:39:49
    
11. FileName =20141007081655.black; BeginDate = 2014-10-07 08:18:05
    
12. FileName =20141007081655.black; EndDate = 2014-10-07 08:18:27
    
13. FileName =20141008083739.black; BeginDate = 2014-10-08 08:38:55
    
14. FileName =20141008083739.black; EndDate = 2014-10-08 08:39:17
    

复制代码

我希望求出每一天从BeginData 到ENDDate 的时间，如何求呢？  谢谢

dengbao2001

在什么环境下啊？

ycilry

利用『 date --date="YYYYMMDD" +%s 』转成秒数后，两个时间相减，再转换再天数；
declare -i date_dem=`date --date="$date2" +%s`   
declare -i date_now=`date +%s`
declare -i date_total_s=$(($date_dem-$date_now))
declare -i date_d=$(($date_total_s/60/60/24))

lkf1100

回复 2# dengbao2001


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