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passwdAuthentiation token manipulation error

>; >; [root at localhost named]# useradd -g users mandy >; >; [root at localhost named]# passwd mandy >; >; Changing password for user mandy. >; >; New password: >; >; BAD PASSWORD: it is too short >; >; Retype new password: >; >; Failed to find entry for user mandy. >; >; >; >; passwd: Authentication token manipulation error 我想去改密码,可是改不了..但是可以正常登陆,这是为什么

by miaho - 内核/嵌入技术 - 2005-03-11 18:19:29 阅读(797) 回复(1)

相关讨论

linux9现在运行passwd改密码,出现如下错误,这该怎么解决,急在线等,谢谢了.

by dgvri - Linux论坛 - 2004-05-23 14:57:04 阅读(2886) 回复(7)

无法修改任何帐户的密码,情况如下: root@FTP /etc# passwd Changing password for user root. New password: Retype new password: passwd: Authentication token manipulation error 运行pwck后的提示: root@FTP /etc# pwck pwck: cannot lock file /etc/passwd Linux版本:Trustix Secure Linux release 2.1 (Horizon) 在线等,谢谢了

by Jiffy - Linux论坛 - 2004-09-23 16:51:38 阅读(852) 回复(1)

在FC4上新建一个帐号,可以登录,但是不能修改密码: [nust@fc4 ~]$ whoami nust [nust@fc4 ~]$ passwd Changing password for user nust. Changing password for nust (current) UNIX password: passwd: Authentication token manipulation error 这个问题怎么解决?

by nust - 系统管理 - 2006-06-06 11:00:30 阅读(939) 回复(2)

#include typedef struct{ int adr[3][3]; }MazeType; main() { MazeType maze; /*maze.adr[3][3]={ {'0','1','1'}, {'1','0','1'}, {'1','1','0'} };*/ maze.adr[3][3] = { {0,1,1}, {1,0,1}, {1,1,0} }; } error information : 13: error: syntax error before '{' token I don't know how to resolve it , Please ... TX a lot

by addictlinux - C/C++ - 2008-12-24 23:08:53 阅读(4486) 回复(5)

db2 insert into DATACORE.ETL_LOGGER values (9999999,'20090411M_SV_ACCM_TIME_PROC','2009-04-11 10:0:55','2009-04-11 10:13:59','ok','M_SV_ACCM_TIME_PROC-success ','M_SV_ACCM_TIME_PROC_D','2009-04-11'); -bash: syntax error near unexpected token `(' 系统是cent linux ,数据库是db2 9 为什么会报这样的错误呢?~

by upperc - Shell - 2009-04-23 15:23:41 阅读(6698) 回复(5)
by liufeinwpu - 程序开发 - 2006-12-20 09:50:25 阅读(863) 回复(1)

在os9中使用Jabbernaut连接jabberd 2.0(Redhat 9 SERVER). 不能注册及登录,在send user name & password的时候出错.查看System log显示 "error:XML parse error (not well-formed (invalid token))" 已经setup /etc/my.cnf (or /var/lib/mysql/my.cnf) and add this: [client] default-character-set=utf8 重启后故障依旧. 服务器环境如下: Redhat 9 Mysql5.0 php5.1.4 我是使用Mysql做为jabberd数据库 请DX指点. Thank You.

by legendpan - 服务器架设 - 2006-05-16 11:53:19 阅读(2733) 回复(2)

运行以下脚本出错,错误如下: wget is /usr/bin/wget --15:36:05-- http://ftp.apnic.net/apnic/stats/apnic/delegated-apnic-latest => `delegated-apnic-latest' Resolving ftp.apnic.net... 202.12.29.20 Connecting to ftp.apnic.net|202.12.29.20|:80... connected. HTTP request sent, awaiting response... 200 OK Length: 844,736 (825K) [text/plain] 100%[================================================...

by yangp881 - 服务器应用 - 2009-05-15 14:44:38 阅读(13576) 回复(2)

#!/bin/bash until [$# -eq 0] do echo "the first perimiter:$1 the num is :$#" shift done

by shengqin - Shell - 2007-06-06 19:05:18 阅读(2652) 回复(3)

复习中.......关于Struts的token checker import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import org.apache.struts.action.Action; import org.apache.struts.action.ActionForm; import org.apache.struts.action.ActionForward; import org.apache.struts.action.ActionMapping; import org.apache.struts.taglib.html.Constants; /* 流程 1. A.jsp 2. A.do : saveToke...

by btpka3 - Java文档中心 - 2009-07-30 11:51:02 阅读(1115) 回复(0)