本帖最后由 eeeee159963 于 2013-02-06 17:23 编辑 [code] def repeater(value): while True: new=(yield value) if new is not None: value=new [/code]怎么跳出while循环
by eeeee159963 - Python - 2013-02-18 11:32:56 阅读(6094) 回复(5)
[code] #!/bin/bash while read line do echo $line for i in 1 2 3 4 5 do if [ $i -eq 3 ] ; then break; #这里结束进程 fi done done
[code]import java.util.*;
public class TestArrayList
{
public static void main(String args[])
{
Object[][] o={{"sd","fh","gd"},{"sf","gd","hds"},{"yr","fh","hgs"},{"sg","fh","hfsd"},{"ut","sg","sgh"},{"jg","jkg","jf"}};
int row=0;
ArrayList al=new ArrayList();
int[] intKey={1,2};
Object[] keyValue={"fh",""};
for(int i=0;i
//检查或修改与指定信号相关联的处理动作(可同时两种操作) static void (*set_signal(int signo,void(*func)(int)))(int) { struct sigaction act,oact; act.sa_handler=func; sigemptyset(&act.sa_mask); act.sa_flags=0; if(signo!=SIGALRM) act.sa_flags|=SA_RESTART; if(sigaction(signo,&act,&oact)<0) return NULL; return(oact.sa_handler); } static void sig_routine(int signo) { switch(signo) { case SI...
RT.. 照着书上敲的代码, 编译运行后发现不能跳出while循环,dev-c++环境. 何解? 谢谢.
[code]
#include
跳出循环: until NUM 执行到一个比当前行号大的行,或者也可以指定在当前frame(我理解成函数)中的某一行 跳出函数: finish 执行,直到选定的frame执行结束,然后打印返回值,将其放入历史值中,停止 本文来自ChinaUnix博客,如果查看原文请点:http://blog.chinaunix.net/u1/44068/showart_697930.html
如 open(FORCEHW,"